119t=-16t^2+119(0)

Solution for 119t=-16t^2+119(0) equation:

119t=-16t^2+119(0)

We move all terms to the left:

119t-(-16t^2+119(0))=0

We get rid of parentheses

16t^2+119t-1190=0

a = 16; b = 119; c = -1190;
Δ = b2-4ac
Δ = 1192-4·16·(-1190)
Δ = 90321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(119)-\sqrt{90321}}{2*16}=\frac{-119-\sqrt{90321}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(119)+\sqrt{90321}}{2*16}=\frac{-119+\sqrt{90321}}{32}
$